So in order to find line AC you must find line AD and DC then plus them together.
to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74
Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6
now plus AD and DC which should give u 11.3
Yes cookies
Are all about the man
It’s not my answer but I think it’s correct!
Answer:
E. 396/538
Step-by-step explanation:
The probability that the senior selected will not be from High School B given that the senior did not answer colege:
First, what's the probability of not having answered college? This will be out denominator.
P(not choosing college) = 244 + 106 + 188 = 538
Next, what's the probability that a senior in that category is not from HS B? Well, add the probabilities that the senior is in HS A or C:
P(senior is in HS A or C and answered not college) = 49 + 99 + 63 + 83 + 31 + 71 = 396
<u>Our answer is E. 396/538.</u>
