The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Answer:
I am attaching a image to understand my proof.
Step-by-step explanation:
PROVE:-
AB = DC
AD = BC
∠ ABD = ∠ BDC (alternate angles are equal )
∠ DBC = ∠ ADB (alternate angles are equal )
∴ Δ ADB ≅ Δ CBD ( by ASA rule )
DC = BA ( corresponding sides of ≅ Δ )
AD = CB ( corresponding sides of ≅ Δ )
Hence it is proved that opposite sides of parallelogram are congruent )
Answer:
If you had 5 apples and Johnny gave you five more how much do you have? Lets count
10 OMG 5+5 is 10
Answer:
dum there is part A prat B and C
Step-by-step explanation: