All categories

2 years ago

Calculate the amount of solvent needed to prepare 50g of 10% solution of Tincture iodine. Name the solvent.

Chemistry

1 answer:

sergeinik [125]2 years ago

7 0

Answer:

Calculate the amount of solvent needed to prepare 50g of 10% solution of tincture Iodine.

Name the solvent

Explanation:

sodium

Hope it is helpful.....

You might be interested in

A watt of is a unit of power equivalent to 1 joule per second (1 J/sec). In other words, a 60 watt light bulb consumes 60 joules

Juli2301 [7.4K]

The time the chocolate bar could power the laptop in hours is 0.00233 hrs.

Since 200 Calories of chocolate bar were burned to power the 100 Watt laptop, we need to find the number of joules on energy in 200 calories of chocolate bar.

Knowing that 4.2 Joules = 1 Calorie, then

200 Calories = 200 × 1 calorie = 200 × 4.2 Joules = 840 Joules

Since the power required by the laptop is 100 W = 100 J/s and Power, P = energy/time

so, time = energy/power

So, the time for the laptop to use 840 J of energy from the chocolate bar at a rate or power of 100 W = 100 J/s is

time = 840 J ÷ 100 J/s = 8.4 s

So, the time in hours is 8.4 s ÷ 3600 s/1 h = 0.00233 hrs (since 1 hr = 3600 s)

So, the time the chocolate bar could power the laptop in hours is 0.00233 hrs.

Learn more about time to power here:

brainly.com/question/17732603

7 0

2 years ago

Water has a density of 1.0g/ml * Physical Property Physical Change Chemical Property Chemical Change

Daniel [21]

The density of water is a physical property.

You can measure it without changing the water to a different substance.

It is not a physical change because the water does not change to ice or steam.

You can observe a chemical property or a chemical change only if the water changes to a different substance.

5 0

2 years ago

When 0.0901 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I

Alexus [3.1K]

Answer:

The heat of combustion for the unknown hydrocarbon is -29.87 kJ/mol

Explanation:

Heat capacity of the bomb calorimeter = C = 1.229 kJ/°C

Change in temperature of the bomb calorimeter = ΔT = 2.19°C

Heat absorbed by bomb calorimeter = Q

$Q=C\times \Delta T$

$Q=1.229 kJ/^oC\times 2.19^oC=2,692 kJ$

Moles of hydrocarbon burned in calorimeter = 0.0901 mol

Heat released on combustion = Q' = -Q = -2,692 kJ

The heat of combustion for the unknown hydrocarbon :

$\frac{Q'}{0.090 mol}=\frac{-2,692 kJ}{0.0901 mol}=-29.87 kJ/mol$

6 0

2 years ago

Read 2 more answers

In a coffee-cup calorimeter, 1 mol NaOH and 1 mol HBr initially at 22.5 oC (Celsius) are mixed in 100g of water to yield the fol

zavuch27 [327]

Answer:

ΔH = -55.92 kJ

Explanation:

Step 1: Data given

1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water

After mixing the temperature rises to 83 °C

Specific heat of the solution = 4.184 J/g °C

Molar mass of NaOH = 40 G/mol

Molar mass of HBr = 80.9 g/mol

Step 2: The balanced equation

NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)

Step 3: mass of NaOH

Mass = moles * Molar mass

Mass NaOH = 1 * 40 g/mol

Mass NaOH = 40 grams

Step 4: Mass of HBr

Mass HBr = 1 mol * 80.9 g/mol

Mass HBr = 80.9 grams

Step 5: Calculate ΔH

ΔH = m*c*ΔT

ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)

ΔH= 220.9 * 4.184 * 60.5

ΔH= 55916.86 J = 55.92 kJ

Since this is an exothermic reaction, the change in enthalpy is negative.

ΔH = -55.92 kJ

4 0

2 years ago

Please help with this been on it for 30 min

yawa3891 [41]

Answer:

470733.12 meters

Explanation:

you'd multiply 65miles by 4.5 to get 292.5 miles then transfer the miles into meters equalling 470733.12 meters

7 0

2 years ago