What is the area of the parallelogram? square units

Calculate the average power required to lift a 750 N object a vertical distance of 10 meters in 4.0 seconds.

Nina [5.8K]

Answer:

500

Explanation:

5 0

2 years ago

How does the transfer of thermal energy occur?

natali 33 [55]

Heat may be transferred by means of conduction, convection, or radiation.

8 0

2 years ago

GUESS WHAT? I'LL MAKE YOU BRAINLIEST! EASY QUESTION!!

avanturin [10]

Here are the 2 reasons:

- Sun damages the eyes

Long-term, unprotected exposure to ultraviolet light from the sun can damage the retina. The retina is the back of the eye, where the rods and cones make visual images, which are then sent to the visual centers in the brain. Damage from exposure to sunlight can also cause the development of cloudy bumps along the edge of the cornea, which can then grow over the cornea and prevent clear vision. UV light is also a factor in the development of cataracts.

- Heat Exhaustion

According to the Centers for Disease Control and Prevention (CDC), heat exhaustion is the body’s response to excessive loss of water and salt, usually through excessive sweating. People working in a hot environment are at risk of heat exhaustion.

6 0

2 years ago

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A 2 m tall, 0.5 m inside diameter tank is filled with water. A 10 cm hole is opened 0.75 m from the bottom of the tank. What is

valina [46]

Answer:

4.75 m/s

Explanation:

The computation of the velocity of the existing water is shown below:

Data provided in the question

Tall = 2 m

Inside diameter tank = 2m

Hole opened = 10 cm

Bottom of the tank = 0.75 m

Based on the above information, first we have to determine the height which is

= 2 - 0.75 - 0.10

= 2 - 0.85

= 1.15 m

We assume the following things

1. Compressible flow

2. Stream line followed

Now applied the Bernoulli equation to section 1 and 2

So we get

$\frac{P_1}{p_g} + \frac{v_1^2}{2g} + z_1 = \frac{P_2}{p_g} + \frac{v_2^2}{2g} + z_2$

where,

P_1 = P_2 = hydrostatic

z_1 = 0

z_2 = h

Now

$\frac{v_1^2}{2g} + 0 = \frac{v_2^2}{2g} + h\\\\V_2 < < V_1 or V_2 = 0\\\\Therefore\ \frac{v_1^2}{2g} = h\\\\v_1^2 = 2gh\\\\ v_1 = \sqrt{2gh} \\\\v_1 = \sqrt{2\times 9.8\times 1.15}$