Answer:
The change in enthalpy for the reaction is 27 kJ/mol.
Explanation:
Volume of the solution = v = 25.0 mL
Mass of the solution = m
Density of the solution = d = 1.0 g/mL
Heat capacity of the solution = C = 4.18 J/g°C
The initial temperature of solution, = 25.8°C
The final temperature of solution, = 21.8°C
Heat loss of the solution = Q
Negative sign indicates that energy is released by the solution.
Energy gained by the ammonium nitrate = Q'
Q'= -Q = 418 J (Conservation of energy)
Mass of ammonium nitrate = 1.25 g
Moles of ammonium nitrate ,n=
Enthalpy change of reaction =