Answer:
(2x + 3) (2(2)x2 – 2+4)
Step-by-step explanation:
thats what i got hope it helps :)
To test if this is a right triangle, let's test these side lengths with the Pythagorean Theorem.
a^2 + b^2 = c^2
c is the hypotenuse, the longest side of a right triangle.
a and b are the legs of the right triangle.
a = 7
b = 15
c = 17
7^2 + 15^2 = 17^2 ?
49 + 225 = 289 ?
274 ≠ 289
Thus, this triangle is not a right triangle since it does not satisfy the Pythagorean Theorem.
Have an awesome day! :)
Answer:
Step-by-step explanation:
If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:
5x-2x^2+1 = 0
This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:
-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.
Use the quadratic formula to solve for x:
First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33
Because the discriminant is positive, the roots of this quadratic are real and unequal.
-b ± √(discriminant)
Applying the quadratic formula x = --------------------------------
2a
we get:
-5 ± √33 -5 + √33
x = ----------------- = --------------------- and
2(-2) -4
-5 - √33
---------------
-4
(2(-2)+9(5)-5)-(6(-2)-4(5)+2)
(-4+45-5)-(-12-20+2)
(45-9)-(-32+2)
36+30
66