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2 years ago

When you translate a finger left does the x-or y-coordinates change

Mathematics

1 answer:

Damm [24]2 years ago

6 0

The x coordinate change

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- 2(x+5) = -2 Directions say solve for the equation

erik [133]

Answer:

x = -4

Step-by-step explanation:

Distribute:

-2(x + 5) = -2

-2(x) -2(5) = -2

Multiply:

-2(x) -2(5) = -2

-2x - 10 = -2

Add 10 on both sides:

-2x - 10 = -2

+10 +10

-2x = 8

Divide by -2 on both sides:

-2x = 8

/-2 /-2

x = -4

3 0

3 years ago

Please help me out!

melisa1 [442]

Answer:

don't under stand your question please

7 0

2 years ago

In the diagram below, the area of $\triangle BCD$ is 60. What is the length of side $\overline{BC}$?

Phantasy [73]

Area of triangle = 1/2 bh

60 = 1/2 (15) h

8 = h

Quadrilateral area = h x (b1 + b2)/2 = 8 x (15+9)/2 = 96 sq units

96 -60 = triangle BAD area = 36 sq units

8 0

2 years ago

Help pls What is the side length of AC

NeTakaya

Answer:

if there are answer choices i would put the closest one to 16

8 0

2 years ago

Which expression is equivalent to

lutik1710 [3]

Answer:

$\frac{\sqrt[4]{3x^2} }{2y}$

Step-by-step explanation:

We can simplify the expression under the root first.

Remember to use $\frac{a^x}{a^y}=a^{x-y}$

Thus, we have:

$\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}$

We know 4th root can be written as "to the power 1/4th". Then we can use the property $(ab)^{x}=a^x b^x$

So we have:

$\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}$

Option D is right.

8 0

3 years ago