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2 years ago

Free electrons may be transferred between bodies by:

2 answers:

8 0

<span>Free electrons may be transferred between bodies by "Contact Action"

When positively charged body comes close to a negatively charged body, then electron flows from positively to negatively charged body

In short, Your Answer would be Option B

Hope this helps!</span>

elixir [45]2 years ago

6 0

Answer:

B) contact action

Explanation:

When two conductors are connected with each other then in that case the free charge of one conductor may be transferred to other if the potential of one conductor is not same as the potential of other conductor.

As we know that positive charge always move from higher potential to lower potential.

So here when two bodies are connected together then in that case electron from one body is transferred to other body if the the potential of two bodies are not same.

So here correct answer will be

B) contact action

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A student discovers that sound waves travel 1,687.5 meters in 5 seconds through air at a temperature of 10°C. Based on this info

vitfil [10]

Answer:

The speed of sound, in m/s, through air at this temperature is 343.5 m/s

Explanation:

Given;

distance traveled by sound, d = 1,687.5 meters

time taken for the sound to travel, t = 5 seconds

air temperature, θ = 10°C

Speed of sound = distance traveled by sound / time taken for the sound to travel

Speed of sound = d / t

= 1687.5 m / 5 s

= 337.5 m/s

Speed of sound at the given temperature is calculated as;

c = 337.5 + 0.6θ

c = 337.5 + 0.6 x 10

c = 337.5 + 6

c = 343.5 m/s

Therefore, the speed of sound, in m/s, through air at this temperature is 343.5 m/s

8 0

2 years ago

A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet

Serga [27]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = $0.27 J$

Explanation:

Force = torque × length

Given

F = 9.13 N

length (L) = 5.91 cm = 0.0591 m [Note 1 m = 100 cm ]

considering the formula above

$9.13 = k * 0.0591$ where k denotes torque

$k = 154.48\ N/m$

Energy Stored $= \frac{1}{2} k x^2$

$= \frac{1}{2} * 154.48 * (0.0591)^2$

$= 0.27J$

8 0

3 years ago

In a closed system, a cart with a mass of 1.5 kg is rolling to the right at 1.4 m/s, while another cart of mass 1.0 kg is rollin

bija089 [108]

Answer: The correct option is (c.).

Explanation:

Mass of the cart A= 1.5 kg

Velocity of Cart A = 1.4 m/s towards right

Mass of the cart B = 1.0 kg

Velocity of Cart B = 1.4 m/s towards left

Momentum (P)= Mass × Velocity

$P_A=1.5 kg\times 1.4 m/s=2.1 kg m/s$

$P_B=1.0 kg\times (-1.4m/s)=-1.4 kg m/s$

(Negative sign means velocity of the cart is in opposite direction of that of the cart A)

Total Momentum = $P_A+P_B=2.10 kg m/s-1.40 kg m/s=0.70 kg m/s$

Hence, the correct option is (c.).

7 0

2 years ago

Read 2 more answers

Which property of gold allows it to be used this way?

densk [106]

the electric conductivity of gold is very high

3 0

2 years ago

On a playground, there is a merry‑go‑round. In order to get it moving, Bonnie applies a force of 31 N31 N . The merry‑go‑round m

nika2105 [10]

Answer:

The magnitude of the torque is 263.5 N.

Explanation:

Given that,

Applied force = 31 N

Distance from the axis = 8.5 m

She applies her force perpendicularly to a line drawn from the axis of rotation

So, The angle is 90°

We need to calculate the torque

Using formula of torque

$\tau=Fd\sin\theta$

Where, F = force

d = distance

Put the value into the formula

$\tau=31\times8.5\sin90$

$\tau= 263.5\ N$

Hence, The magnitude of the torque is 263.5 N.

4 0

2 years ago