The freezing point depression is a colligative property which means that it is proportional to the number of particles dissolved.
The number of particles dissolved depends on the dissociation constant of the solutes, when theyt are ionic substances.
If you have equal concentrations of two solutions on of which is of a ionic compound and the other not, then the ionic soluton will contain more particles (ions) and so its freezing point will decrease more (will be lower at end).
In this way you can compare the freezing points of solutions of KCl, Ch3OH, Ba(OH)2, and CH3COOH, which have the same concentration.
As I explained the solution that produces more ions will exhibit the greates depression of the freezing point, leading to the lowest freezing point.
In this case, Ba(OH)2 will produce 3 iones, while KCl will produce 2, CH3OH will not dissociate into ions, and CH3COOH will have a low dissociation constant.
Answer: Then, you can predict that Ba(OH)2 solution has the lowest freezing point.
3. There are more oxygen atoms on the reactant side than the product side
It rusts more in wet climates because it is water and when water hits the automobile there is a chemical reaction. If the water is salt water it will cause it to rust quicker.
Answer:
1 mole of molecules = 6.022 × 10²³ molecules
1 = 6.022 × 10²³ molecules / mole
Multiplying a number with [6.022 × 10²³ molecules / mole] is like multiplying the number with 1 so 0.877 mole × 6.022 × 10²³ molecules / mole = 5.28 × 10²³ molecules
5.28 × 10²³ molecules of water is produced.
Explanation:
Answer:
The new volume is 808L.
Explanation:
First, you need to set up your proportion, using Charles's law.
V1 V2
<u> </u> = <u> </u>
T1 T2
Then, substitute for the ones you already know.
625 L V2
<u> </u> = <u> </u>
273 K 353 K
Then, you need to cross multiply.
625 x 353 = 273 x V2
Then, solve for V2.
220625 = 273 x V2
220625 ÷ 273 = V2
808 = V2
The final volume is 808L.