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2 years ago

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One cooy machine can run off copies in 198 minutes. A newer machine can do the same job in 126 minutes. How long does it take th

e two machines, working together, to make all of the necessary copies?

1 answer:

yanalaym [24]2 years ago

4 0

This depends on the necessary number of copies.

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2 years ago

Which represents the solution(s) of the equation x^2= 289

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Answer:

x² is equal to 289 so x is obviously the square root of 289 which is 17

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2 years ago

What is the value of x? <br> (x + 40)° (3x)°<br><br> A. 20<br> B.35 <br> C. 60<br> D. 70

Olenka [21]

Hello!

We are given the equation below.

x+40=3x

We want to get all of the variables on side. First of all let's subtract 40 from both sides.

x=3x-40

Now we rearrange our equation so the commutative property will work.

x=3x+(-40)
x=-40+3x

Now we subtract 3x from both sides.

-2x=-40

We divide both sides by -2.

x=20

Our answer is A) 20.

I hope this helps!

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2 years ago

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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

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2 years ago

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