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2 years ago

The singing of an opera singer caused a drinking glass to shatter. Explain this using what you know about resonance.

Physics

2 answers:

rusak2 [61]2 years ago

5 0

Explanation:

Resonance: Resonance is the phenomenon which occurs when the applied frequency on the object is equal to its natural frequency.

In the given problem, the singing of an opera singer caused a drinking glass to shatter.

This occurs due to the phenomenon resonance. The applied frequency of the singing of an opera singer on the drinking glass matches with the natural frequency of the drinking glass. It causes a glass to shatter.

erma4kov [3.2K]2 years ago

3 0

The singing of the opera singer matched the natural frequency of the glass, causing it to vibrate. The strong vibrations caused the glass to shatter.

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At t=0 bullet A is fired vertically with an initial (muzzle) velocity of 450 m/s. When 3s. bullet B is fired upward with a muzzl

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Answer:

At time 10.28 s after A is fired bullet B passes A.

Passing of B occurs at 4108.31 height.

Explanation:

Let h be the height at which this occurs and t be the time after second bullet fires.

Distance traveled by first bullet can be calculated using equation of motion

$s=ut+0.5at^2 \\$

Here s = h,u = 450m/s a = -g and t = t+3

Substituting

$h=450(t+3)-0.5\times 9.81\times (t+3)^2=450t+1350-4.9t^2-29.4t-44.1\\\\h=420.6t-4.9t^2+1305.9$

Distance traveled by second bullet

Here s = h,u = 600m/s a = -g and t = t

Substituting

$h=600t-0.5\times 9.81\times t^2=600t-4.9t^2\\\\h=600t-4.9t^2 \\$

Solving both equations

$600t-4.9t^2=420.6t-4.9t^2+1305.9\\\\179.4t=1305.9\\\\t=7.28s \\$

So at time 10.28 s after A is fired bullet B passes A.

Height at t = 7.28 s

$h=600\times 7.28-4.9\times 7.28^2\\\\h=4108.31m \\$

Passing of B occurs at 4108.31 height.

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