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2 years ago

7

If the product of the two slopes of two lines equals -1, then the lines are ?

1 answer:

VladimirAG [237]2 years ago

7 0

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{a}{b}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{b}{a}}\qquad \stackrel{negative~reciprocal}{-\cfrac{b}{a}}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \left( \cfrac{a}{b} \right)\left( -\cfrac{b}{a} \right)=-1~\hfill$

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RoseWind [281]

Answer:

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Step-by-step explanation:

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3 years ago

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aliya0001 [1]

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

LekaFEV [45]

Answer: $y-1=\dfrac32(x+3)$

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

In graph(below) given line is passing through (-2,-4) and (2,2) .

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Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope = is given by

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