Answer:
When Amina is 18. Saad would be;
k. 14
Step-by-step explanation:
Let "x" represent Anita's current age and let "y" represent Saad's current age, we have;
Anita's age = 2 × Saad's age
Therefore;
x = 2 × y...(1)
In 4 years, we will get;
x + 4 = 1.5 × (y + 4)...(2)
Substituting the value of x in equation (1) into equation (2), we get;
2·y + 4 = 1.5·y + 1.5 × 4 = 1.5·y + 6
2·y + 4 = 1.5·y + 6
2·y - 1.5·y = 6 - 4 = 2
0.5·y = 2
y = 2/0.5 = 4
Saad's current age = y = 4 years
From equation (1), we have;
x = 2 × y = 2 × 4 = 8
Amina's current age = x = 8 years
When Amina is 18, we have;
18 = 10 + 8 = 10 + x
Therefore, Amina would be 18 in 10 years time from now, from which we have;
Saad would be 10 years + y = 10 years + 4 years = 14 years in 10 years from now
Therefore, when Amina would be 18 years in 10 years from now Saad would be 14 years.
Answer: P(22 ≤ x ≤ 29) = 0.703
Step-by-step explanation:
Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = output of the machine in ounces per cup.
µ = mean output
σ = standard deviation
From the information given,
µ = 27
σ = 3
The probability of filling a cup between 22 and 29 ounces is expressed as
P(22 ≤ x ≤ 29)
For x = 22,
z = (22 - 27)/3 = - 1.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.047
For x = 29,
z = (29 - 27)/3 = 0.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.75
Therefore,
P(22 ≤ x ≤ 29) = 0.75 - 0.047 = 0.703
The answer is 350.
<em>
m= minutes</em>
Plan 1: 9+0.13<em>m</em>
Plan 2: 23+0.09<em>m</em>
9+0.13<em>m</em> = 23+0.09<em>m</em>
-9 -9
0.13<em>m</em> = 14+0.09<em>m</em>
-0.09<em>m</em> -0.09<em>m</em>
0.04<em>m</em>= 14
14÷0.04= 350
<em>m</em>= 350
The mean is the average.
Add all the number of pets and divide by how many people there were.
3+5+2+4+1
15/number of people
15/5
=3
Hope this helps :)