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2 years ago

Help me plssss 30 pointsssssss

Physics

2 answers:

labwork [276]2 years ago

6 0

Answer:

Explanation:

viva [34]2 years ago

5 0

Answer:

Light

sound

electrical

chemical

mechanical

Explanation:

Hope this helps!!

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A mover applies a net force of 28 N to a sofa that has a mass of 70 kg.

Alinara [238K]

Answer: .4 m/s^2= acceleration

Explanation:

f = m*a

We can rearrange this equation to solve for acceleration. Therefore,

a=f/m

a= 28N/70kg

a= 0.4 m/s^2

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2 years ago

The (blank) of vibration of a wave is defined as that which has the lowest frequency

saveliy_v [14]

Fundamental frequency

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An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char

ArbitrLikvidat [17]

Answer:

Part a)

$W = 1.58 \times 10^{-20} J$

Part b)

$v = 1.86 \times 10^5 m/s$

Explanation:

Part a)

Electric field due to large sheet is given as

$E = \frac{\sigma}{2\epsilon_0}$

$\sigma = 4.00 \times 10^{-12} C/m^2$

now the electric field is given as

$E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}$

$E = 0.225 N/C$

Now acceleration of an electron due to this electric field is given as

$a = \frac{eE}{m}$

$a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}$

$a = 3.97 \times 10^{10}$

Now work done on the electron due to this electric field

$W = F.d$

$d = 0.470 - 0.03$

$d = 0.44 m$

So work done is given as

$W = (ma)(0.44)$

$W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)$

$W = 1.58 \times 10^{-20} J$

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

$W = \frac{1}{2}mv^2 - 0$

$1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2$

$v = 1.86 \times 10^5 m/s$

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2 years ago

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gfdschhgfdxcvhgfd

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Manufacturer claims its cleanser works twice as fast as any other. What tests could be performed to support this claim ? Explain

blagie [28]

get this cleanser and a different one.

get some dirt.

get two clocks

put equal amounts od cleanser on the dirt and start both clocks

when one has workred stop its clock. same for other.

compare times

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