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2 years ago

Select strong association, weak association, or moderate association to correctly classify the correlation coefficient.

Mathematics

2 answers:

11Alexandr11 [23.1K]2 years ago

4 0

Answers:

0.45 is a moderate association

0.95 and -0.8 are both strong association

0.10 is weak association

Explanation:

This is the interpreation of the correltaion coefficient:

1) The correlaion coefficient assesses the relationship between two variables in a scatter plot.

2) If the sign of the correlation coefficient is positive means that the two variables trend to grow or decrease in the same sense. This is an uphill line or curve: if variable X grows, variable Y grows, and if variable X decreases variable Y grows.

If the sign of the correlation coefficient is negative means that the two variables go in opposite direction. This is a downhill line or curve.

3) A correlation coefficient of +1 or -1 is a perfect association. The two variables are totally associated.

4) A correlation coefficient less that +1 but greater than 0.7 is a strong association. The same with a coefficite between - 0.7 and -1.

5) A correlation coefficient arroun +0.5 or -0.5 is a moderate association.

6) A correlation coefficient of 0 is a nill association.

7) A correlation coeffiicient between 0 and 0.3 is a weak association. The same when the correlation coefficient is between -3 and 0.

FrozenT [24]2 years ago

3 0

Answer:

Just took it!

Step-by-step explanation:

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Some parts are missing in the queston. Find attached the picture with the complete question

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$\large\boxed{\large\boxed{161}}$

Explanation:

Let's put the information in a table step-by step.

(number of remaining students)

Juniors Seniors

Condition

Initially J S

15 seniors left S - 15

Twice juniors as seniors 2(S - 15)

3/4 of the juniors left 1/4×2(S - 15)
1/3 of seniors left 2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

2/3×(S - 15) - 1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

$2/3\times (S - 15) - 1/4\times 2(S - 15) = 8$

Mutilply all by 12:

$8(S - 15)-6(S - 15)=96$

Distribution property:

$8S-120-6S-90=96$

Addtion property of equalities:

$8S-6S=96+120+90$

Add like terms:

$2S=306$

Division property of equalities:

$S=306/2=153$

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

$2/3\times (S-15)+1/4\times 2(S-15)$