If f is a smooth function, then curl(gradf) = 0 i + 0 j + 0 k . true or false

1 answer:

7 0

The correct answer for the given statement above would be TRUE. Yes it is true that if <span>f is a smooth function, then curl(gradf) = 0 i + 0 j + 0 k. I hope this is the answer that you are looking for. Thank you for posting your question in brainly. </span>

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Equation through the point (5,9) with a slope of -4

hoa [83]

The answer is: y=-4x+29

To solve this, you need to know the y-intercept.
1. y=-4x+b
2. 9+-4(5)+b
3. 9=-20+b
4. b=9+20
5. b=29
6. Substitute into y=-4x+b

4 0

2 years ago

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the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width

-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

$\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}$

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

$\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}$

On solving the above expression for x we get

$\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}$

$\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}$