What is the lateral surface area of a cylindrical-shaped candle with a radius of 3 cm and a height of 15 cm? (Use 3.14 for .) A.
847.8 sq cm B. 45 sq cm C. 282.6 sq cm D. 339.12 sq cm
1 answer:
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The correct answer is: <span>The graph shifts 5 units right
Explanation:
Below is the graph attached of both the equations:
Red line: Represents f(x) = </span><span>2x + 2.
Blue line: Represents g(x) = 2x - 3.
As you can see in the graph that g(x) is shifted 5 units right to f(x).
If you move towards right by 1 unit, you have to subtract 1 from f(x) until you reach g(x) like:
2x + 2 - 1 = 2x + 1 (1 unit)
</span>2x + 1 - 1 = 2x (1 unit)
2x - 1 = 2x - 1 (1 unit)
2x - 1 -1 = 2x - 2 (1 unit)
2x -2 - 1 = 2x -3 (1 unit)
Total 5 units.
Hence the correct answer is t<span>he graph shifts 5 units right.</span>
Explanation:
Below is the graph attached of both the equations:
Red line: Represents f(x) = </span><span>2x + 2.
Blue line: Represents g(x) = 2x - 3.
As you can see in the graph that g(x) is shifted 5 units right to f(x).
If you move towards right by 1 unit, you have to subtract 1 from f(x) until you reach g(x) like:
2x + 2 - 1 = 2x + 1 (1 unit)
</span>2x + 1 - 1 = 2x (1 unit)
2x - 1 = 2x - 1 (1 unit)
2x - 1 -1 = 2x - 2 (1 unit)
2x -2 - 1 = 2x -3 (1 unit)
Total 5 units.
Hence the correct answer is t<span>he graph shifts 5 units right.</span>