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2 years ago

What is the value of c so that -12 and 12 are both solutions of x^2-c=108?

Mathematics

1 answer:

murzikaleks [220]2 years ago

8 0

Answer:

c=36

Step-by-step explanation:

Because $x^2-c=108$ can be rewritten as $x^2-c-108=0$ , finding the value of c so that x=(+-)12 solves this equation it means to find the value of c so that $(+-)12^2-c-108=0$ .
Because $12^2=(-12)^2=144$ , we must find c so that $144-c-108=0$ .
Because $144-108=36$ , c=36.
To check, replace c=36 in the initial equation, and check it is a solution for x=(+-)12.

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Jkl is an equilateral triangle jk= 13x+5,KL= 17X-19 AND JL= 8X+35

stira [4]

Answer:

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Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

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2 years ago

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2 years ago

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natulia [17]

Answer:

Molly's estimation was approximately correct.

Step-by-step explanation:

Given:

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2 years ago

What is the value of c so that -12 and 12 are both solutions of x^2-c=108? ​

What is the value of c so that -12 and 12 are both solutions of x^2-c=108?