How many atoms are present in 179.0 g of iridium? include units please:)!

Chemistry

2 answers:

pentagon [3]2 years ago

6 0

Answer:

A. 5.606x10²³atoms

Explanation:

denpristay [2]2 years ago

5 0

Answer:

179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms / 1 mol ) = 5.61 x 10^23 atoms of iridium

Explanation:

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