(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
Answer:
11 2/3 pounds
Step-by-step explanation:
If a pack contain 1 2/3 pounds, 7 packs would contain :
1 2/3 x 7
× 7 = 35/3 = 11 2/3 pounds
3/8 meters squared because 3/4x1/2 = 3/8m
Ok so this is how you do it.....
You need to get x by itself.
8x + c = k
Subtract c.
8x = k - c
Divide 8 from both sides.
x = k - c / 8
I hope this helps love! :)
Answer: X > 100
Step-by-step explanation:
X - 19 < 81
Once the less than sign is turned over
X > 81 +19
X > 100
Thus, the value of X must be greater than 100