The upper quartile for the data set given below is. 14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29
LekaFEV [45]
Ok, first we need to organize.
<span>14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29
</span>3, 8, 9, 11, 12, 14, 17, 22, 23, 27, 29.
First, we need to find the median, the or the middle, which is 14.
Now that we know the median is fourteen, we take away all numbers to the left of 14, including 14: 17, 22, 23, 27, 29. Now just find the median in this new set of numbers. This will give us our upper quartile, which is 23. Hope this helped, and don't forget to drop a like.
So we have
h=hits
m=miss
h+m=10
gain 5 for every hit and lose 3 for every miss
so 5 times number of hit=points from hit
-3 times number of miss=points deducted from miss
add
5h-3m=18
so we have the equations
h+m=10
5h-3m=18
multiply first equation by 3
3h+3m=30
add to first equatio
3h+3m=30
<u>5h-3m=18 +</u>
8h+0m=48
8h=48
divide by 8
h=6
subsitute
h+m=10
6+m=10
subtract 6
m=4
6 hits
4 miss
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Answer:
C. 1
Step-by-step explanation:
We can see that each box in the grid is one unit.
We count one box to the right on the horizontal axis and 4 boxes down on the vertical axes to obtain the components of vector v.
See graph in attachment.
Therefore the components of vector v is
.
The length of the x component is 1 unit
Hence the correct answer is C.