Answer:
three consecutive odd integers: 2n-1 2n+1 2n+3
that the sum of the smaller two is three
times larger increased by seven: 2n-1 + 2n+1 = 3(2n+3) +7
4n = 6n+ 9 +7
4n = 6n+ 16
4n -6n = 16
-2n = 16
n = 16/(-2)
n=-8
a) 2n -1 = 2(-8) -1 = -17
b) 2n+1 = 2(-8)+1 = -15
c) 2n+1 = 2(-8)+3 = -13
Ans. -17 ; -15 ; -13
Please, use ( ) around fractional coefficients:
<span>1/3x-9y, 6/5x-15y should (probably) be written as (1/3) - 9y and (6/5)x - 15 y.
The LCD here is 3(5) = 15.
Mult. </span><span>1/3x-9y and 6/5x-15y by 15, and then divide the result by 15:
</span>15 [ (1/3)x - 9y and (6/5)x - 15 y ]
---------------------------------------------
15
This simplifies to:
5x - 135y and 18x - 225y
------------ --------------
15 15
These fractions are equivalent to the original ones, but now the common denominator, 15, is evident.
The next number in the series is 30.
<h3>What is series?</h3>
It should be noted that series simply means the operation of adding values together in a data set.
In this case, it can be seen that the numbers are interchangeable between 30 and 31.
In this case, since 31 was the last number, the next number will be 30.
Learn more about series on:
brainly.com/question/24295771
#SPJ1
90/110 reduces to 9/11. Good luck!
