The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0
Thus, the equation of the trend line, in variables K and J, is
K = 2J + 28
Since he lost 5 every month, it should be that the slope is -5, not 5, he is not gaining 5 every month
yint is 100 and slope is -5 would be correct
b=-5m+100
b=number of blocks he has after m months
Answer:
0.4069 ; 1.843
Step-by-step explanation:
Given:
Base of parallelogram, b = (2x - 1)
Height = (4x - 7)
Area = 1
Area of parallelogram = Base * height
Area of parallelogram = (2x - 1) * (4x - 7)
(2x - 1) * (4x - 7) = 1
8x² - 14x - 4x + 7 = 1
8x² - 18x + 7 - 1 = 0
8x² - 18x + 6 = 0
Divide through by 2
4x² - 9x + 3 = 0
Solving the quadratic equation :
Using the formula
-b ± √(b² - 4ac) / 2a
a = 4 ; b = - 9 ; c = 3
Plugging in the values :
-(-9) ± √((-9)² - 4(4)(3)) / 2(4)
9 ± √(81 - 48) / 8
9 ± √33 / 8
(9 ± 5.7445626) / 8
(9 - 5.7445626) / 8) = 0.4069
(9 + 5.7445626) / 8 = 1.843
