Answer:
choice 2) x+2y+3 = 7
Step-by-step explanation:
equation to match:
x+2y = 4
add 3 to each side
x+2y+3 = 7 (which is the same as choice 2, x+2y+3 = 7)
The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
Answer:
9.83
Step-by-step explanation:
x2 + 4x- 59 = 0 +59
x2 + 4x = 59
6x=59
6x/6 = 59/6
x=9.83
I dont understand the question
Answer: Answer is (D)
Step-by-step explanation:
I got the answer correct on Edg.
