Answer:
4 trays should he prepared, if the owner wants a service level of at least 95%.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 5
Standard Deviation, σ = 1
We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.
Formula:
P(X > x) = 0.95
We have to find the value of x such that the probability is 0.95
P(X > x)
Calculation the value from standard normal z table, we have,
Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.
The answer is a = 
Step-by-step explanation:
<em>1. Convert the mixed fraction to an improper fraction</em>
To find the numerator, multiply the denominator by the whole number and add the numerator to it.
The denominator remains the same.
So, 2
will be 
<em>2. Now the equation is,</em>
a - 
a = 
+ a
<em>3. Take LCM on both sides. </em>
For the left side, multiply the first fraction by 
and multiply the second fraction by 
a - 
a = 
<em>4. Solve by making a the subject</em>
=
=
=10+8a
= 10 + 8a
a = 2(10 + 8a)
a = 20 + 16a
a-16a = 20
-15a = 20
a = 
a =
Therefore, the answer is a =
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Answer:
2.112
Step-by-step explanation:
don't have one
Answer:
The lcm is 48. Hope this helps
