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2 years ago

8

A line segment has endpoints j (2,4) and L (6,8). The point K is the midpoint of JL. What is an equation of a line perpendicular

of JL and pass through K?
A. Y=- x +10
B. Y=- x - 10
C. Y= x + 2
D. Y= x- 2

1 answer:

algol [13]2 years ago

4 0

C.Y=x+ 2 is the answer to this question

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Answer:

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<u>Equation of a circle</u>

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Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

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Collect like terms and subtract 4 from both sides:

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