The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.
so airspeed due west is = net speed - speed of plane = 240-220= 20 km/h.
airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.
the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h
the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.
if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.
so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.
the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.
Answer:
b. they can be observed and measured
Explanation:
Matter is anything that has weight and occupy space. There are three states of matter namely Solid, liquid and gas.
The properties of matter are both physical and chemical in nature. Both properties can be measured and observed. Phhysical properties are anything that can be measured without changing the state of the matter. Example of physical properties includes mass, volume, length, color etc.
Chemical properties is another properties of matter. This is the ability of the states of matters to combine with other substance to form a new product for example, rusting of iron, formation of salt etc.
All this as discussed are both measurable and can be observed.
Answer:
10.0 zero, by Gauss' Law the symmetrical distribution will produce no internal electric fields
21.5 E = k Q / R^2 behaves as if all charge were at center
E = 9 E9 * 29.5 E-6 / .215^2 = 5.74E6 N/C
Then the maximum height of the catapult will be 69.78 meters.
<h3>What is kinematics?</h3>
The study of motion without considering the mass and the cause of the motion. The equation of motion is given below.
v = u + at
s = ut + (1/2)at²
v² = u² + 2as
A catapult can project a projectile at a speed as high as 37.0 m/s. (a) if air resistance can be ignored.
a = - 9.81 m/s²
u = 37 m/s
v = 0
s = h
Then the maximum height of the catapult will be given by the third equation.
v² = u² + 2as
0² = 37² - 2 × 9.81 × h
h = 37² / (2 × 9.81)
h = 69.78 meters
Then the maximum height of the catapult will be 69.78 meters.
More about the kinematics link is given below.
brainly.com/question/7590442
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