Well assuming we have all of these, earth
Answer:
The molarity of this final solution is 0.167 M
Explanation:
Step 1: Data given
Volume of a 0.100 M HNO3 solution = 50.0 mL
Volume of a 0.200 M HNO3 = 100.0 mL
Step 2: Calculate moles
The final molarity must lie between 0.1M and 0.2M
Moles = molarity * volume
Moles HNO3 in 50mL of a 0.100M solution = 0.05 L *0.100 M = 0.005 mol
Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol
total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L
Step 3: Calculate molarity of final solution
Molarity = mol / volume
Molarity 0.025 moles /0.150 L
Molarity = 0.167M
The molarity of this final solution is 0.167 M
Answer:
The correct answer is B the tertiary halides reacts faster than primary halides.
Explanation:
During SN2 reaction the nucleophile attack the alkyl halide from the opposite side resulting in the formation of transition state in which a bond is not completely broken or a new bond is not completely formed.
After a certain period of time the nucleophile attach with the substrate by substituting the existing nuclophile.
An increase in the bulkiness in the alkyl halide the SN2 reaction rate of that alkyl halide decreases.This phenomenon is called steric hindrance.
So from that point of view the that statement tertiary halides reacts faster that secondary halide is not correct.
Answer:
h = 0.346 m
Explanation:
mercury barometer:
∴ Pa = 0.455 atm = 46102.875 Pa = 46102.875 Kg/ms²
∴ ρ = 13600 Kg/m³
∴ g = 9.80 m/s²
⇒ h = (46102.875 Kg/ms²) / (13600 Kg/m³ )(9.80 m/s²)
⇒ h = 0.346 m
Potassium phosphate and water will be formed