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2 years ago

Sam evaluated the expression x2y for x = 7 and y = 9. He got a value of 49. Which of the following statements is correct?

1 answer:

3 0

Sam forgot to multiply

he added x and 2, which is actually 7 and 2, and multiplied that by 9
however, he was supposed to multiply 7 and 2 and 9 all together

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Find 8 /10 + 7 /100

Sergio [31]

Answer:

——— = 0.87000

100

Step-by-step explanation:

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2 years ago

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45 45 90<br> This question is using the 45 45 90 rule can someone help

AleksAgata [21]

Answer:

x= 4.24

y= 4.24

Step-by-step explanation:

1) I began by analyzing the given number, which in this case is the hypotenuse. I know the hypotenuse is equal to x√2.

2) I divided 6 by √2, which gave me 4.24.

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2 years ago

In a 4x4x4 cube, the face is painted red, then divided into 64 1x1x1 cubes. How many of the 1x1x1 cubes are painted 1 or 2 faces

WITCHER [35]

Is 28 I think I am not sure

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2 years ago

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Maya says that value of the 6 in 0.006 is 1/10 of the value of the 6 in 0.6 . Is she correct? Explain

Nikolay [14]

Answer:

Maya is NOT correct as

$\frac{1}{1000}$ is 1/100 of the value $\frac{1}{10}$

Step-by-step explanation:

The value of 6 in 0.006 = $\frac{1}{1000}$

Also, the value of 6 in 0.6 = $\frac{1}{10}$

But, $\frac{1}{1000}$ is not 1/10 of the value $\frac{1}{10}$

as 1/10 of the value $\frac{1}{10}$ = $\frac{1}{100}$

Hence,Maya is NOT correct.

$\frac{1}{1000}$ is 1/100 of the value $\frac{1}{10}$

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2 years ago

There are 5 questions on a multiple choice exam, each with five possible answers. If a student guesses on all five questions, wh

Mrac [35]

Answer:

$20.5\%$

Step-by-step explanation:

Let's write out a case for two specific questions being correct and the rest being incorrect:

$\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}$ ,

The $\frac{1}{5}$ represents the chances of getting the question correct, as there are 5 answers and 1 correct answer choice.

The $\frac{4}{5}$ represents the chances of getting the question incorrect, as there are 5 answers and 4 incorrect answer choices.

The equation above does show the student getting two answers correct and three answers incorrect, but it only shows one possible case of doing so.

We can choose any two of the five questions to be the ones the student gets correct. Therefore, we need to multiply this equation by the number ways we can choose 2 from 5 (order doesn't matter): $\binom{5}{2}=10$ .

Therefore, the probability the student gets two questions correct is:

$\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \binom{5}{2}=\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot 10=0.2048\approx \boxed{20.5\%}$

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2 years ago