Answer:
(a) adding 0.050 mol of HCl
Explanation:
A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.
In the buffer:
1.0L × (0.10 mol / L) = 0.10 moles of HF -<em>Weak acid-</em>
1.0L × (0.050 mol / L) = 0.050 moles of NaF -<em>Conjugate base-</em>
-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-
Thus:
<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.
(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.
(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>
Answer: 9.27 g of Na
Explanation:Please see attachment for explanation
It wouldn’t be a good idea bc metal absorbs the weather around it. so in florida it would be too hot and in alaska it would be too cold!
Answer:
D. To ensure the cooling process is not affected by surrounding temperature
Explanation:
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Answer:
Number of moles of chlorine = 3.38 mol
Explanation:
Given data:
Mass of chlorine = 120 g
Moles of chlorine = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of chlorine = 35.5 g/mol
Now we will put the values in formula.
Number of moles = 120 g/ 35.5 g/mol
Number of moles = 3.38 mol