Answer:
0.45 moles
Explanation:
The computation of the number of moles left in the cylinder is shown below:
As we know that
we can say that
where,
n1 = 1.80 moles of gas
V2 = 12.0 L
And, the V1 = 48.0 L
Now placing these values to the above formula
So, the moles of gas in n2 left is
= 0.45 moles
We simply applied the above formulas so that the n2 moles of gas could arrive
Answer:
Average of the trial is: 288.50 C
Percent Error: 3.83%
Explanation:
(291 + 287 + 295 + 281) : 4 = 288.50 C
Average: 288.50 C
Percent Error: {(300 - 288.50) : 300} x 100% = 3.83 %
<span>2 HCl + Ba(OH)2 = BaCl2 + 2 H2O is the answer.</span>
The chemical equation for the combustion of methane is CH4 + 2O2 --> CO2 + 2H2O.
The coefficients of that equation are 1, 2, 1, and 2, in the order you asked for.
Answer:
Explanation:
molarity is moles of solute/L solution
5.5 g 1 moles Kl 1000 mL
_____ * __________ * ________ = 0.22088 M
150 ml of solution 166 grams 1 L
(39 grams K+ 127 grams I) ^