Answer:
-7612.5 kJ.
Explanation:
Equation of the reaction:
C18H36O2 + 26O2(g) --> 18H2O(g) + 18CO2(g)
ΔHrxn = ΔHp - ΔHr
ΔH (combustion) = [18*(ΔHf of CO2) + 18*(ΔHf of H2O)] - [1*(ΔHf of C18H36O2) + 26*(ΔHf of O2)]
= [18 * (-394) + 18 * (-242)] - [1 * (-948) + 26 * (0)]
= [(-7092) + (-4356)] - (-948)]
= -10500 kJ/mol
Molar mass:
C18H36O2;
= (18*12) + (36*1) + (2*16)
= 284 g/mol
O2:
= (2 * 16)
= 32 g/mol
Number of moles = mass/molar mass
C18H36O2:
= 206/284
= 0.725 mol.
O2:
= 943.2/32
= 29.475 mol
Finding the limiting reagent,
By stoichiometry, 1 mole of steric acid combusted in 26 moles of oxygen.
Therefore,
= 29.475 mol of O2 * 1 mol of steric acid/26 mol of O2
= 1.134 mol of steric acid(only 0.725 mol is present)
Steric acid is the limiting reagent.
q = n * ΔHrxn
= 0.725 * -10500
= -7612.5 kJ.
Answer:
g/100g
Explanation:
grams per 100 g of solvent or short term g/100g
Only writing this because need to ask a question sorry
D is the answer as shale are deposited in slow moving water and are often found in river deltas,on flood plains and offshore from beach sands. They can also be deposited in sedimentary basins and on the continental shelf, in relatively deep and quiet water.