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2 years ago

What is the definition of electrical energy?

1 answer:

7 0

Answer: Electrical energy is defined as an electric charge that lets work be accomplished. An example of electrical energy is power from a plug outlet. YourDictionary definition and usage example.

Explanation:

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An atom of oxygen (atomic number 8) has a mass number of 17. How many neutrons are<br> in that atom?

ludmilkaskok [199]

<h2>Answer: # of neutrons = 9</h2>

<h3>Explanation:</h3>

# of neutrons = mass number - atomic number

= 17 - 8

= 9

<h3>∴ number of neutrons in an atom of oxygen of mass number 17, is 9.</h3>

3 0

1 year ago

Mario wants to split a beam of white light into different colors. Which tool will work best?

cestrela7 [59]

The correct answer --> A

7 0

2 years ago

PLEASE HELP ME THIS IS DUE RN I HAVE NO IDEA I WILL MARK BRAINLIEST I JUST NEED HELP

djverab [1.8K]

Answer:

3.45 × 10^5

=3.45^5

I hope this helps

6 0

2 years ago

While 1 gram of fat provides 9 calories, 1 gram of glucose provides 4 calories. Why is that?

seropon [69]

Answer:

fat always has more calories than glucose does

Explanation:

hope hope this helps!

6 0

2 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0

2 years ago