Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,
Taking last two ratio,
Putting the value of BC , AC ,∠A,∠B
≈734.106 miles
Therefore they are 734.106 miles apart.
Answer:
GCF of 40 26 8
40=2×2×2×5
26=2×13
8=2×2×2
=2 is common in them
Step-by-step explanation:
the answer is 2
Answer:
should be 2 excluding the start (origin)
Step-by-step explanation:
F(0) = -1/5
f(4) = 7/17
f(4) - f(0)
average rate of change = --------------
4 - 0
(7/17) - (-1/5)
average rate of change = ---------------------
4
52/85
average rate of change = ---------
4
average rate of change = 52/85 *4
average rate of change = 208/85