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2 years ago

7

In mr. B classroom, there are 29 students. Twelve students got a B, one got a C and the rest have A. What percent of the class r

eceived an A.

2 answers:

Gennadij [26K]2 years ago

7 0

Answer:

55.172 percent

Step-by-step explanation:

Tanya [424]2 years ago

7 0

55.172413793103 percent

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I also need help with this one

icang [17]

It is c.

explanation:

20+130+h =180

when you solve you get h=50

130+g = 180

g= 50

50+60+f = 180

f=70

7 0

2 years ago

Read 2 more answers

___ L = 240 kL ? <br><br> A. 24,000<br> B. 240,000<br> C. 0.240<br> D. 2.4

koban [17]

It's b 240000
I'm sorry if wrong I'm not too good at these things

6 0

2 years ago

Read 2 more answers

Which of the following correctly shows the quadratic formula for the given equation? 3x2 - 6x + 8 = 0

frez [133]

The quadratic formula is expressed as:

x = (-b +/- √(b^2 - 4ac) ) / 2a

where a, b and c are the coefficients of the quadratic equation with the form ax^2 + bx + c=0

Therefore, the quadratic equation would be:

a = 3
b = -6
c = 8

x = (-(-6) +/- √((-6)^2 - 4(3)(8) ) / 2(3)

Hope this helps.

7 0

2 years ago

Han spent 75 minutes practicing the piano over the weekend. Tyler practiced the clarinet for 64% as much time as Han practiced t

prisoha [69]

Answer: Priya practiced for <u>189 minutes </u>

Tyler practiced for <u>123 minutes </u>

-------------------------------------------------------------------------------------------------------------

The Explanation: Now, Han spent 75 minutes practicing the piano over the weekend

Then, Priya practiced the violin for 152% as much time as Han practiced the piano.

Priya = 152% of 75 minutes + 75 minutes

= 152/100 × 75 + 75

= 1.52 × 75 + 75

= 114 + 75

= 189 minutes

Finally, Priya practiced for <u>189 minutes</u>

-------------------------------------------------------------------------------------------------------------

Tyler practiced the clarinet for 64% as much time as Han practiced the piano.

Tyler = 64% of 75 minutes + 75 minutes

= 64/100 × 75 minutes + 75 minutes

= 64 / 100 × 75 + 75

= 0.64 × 75 + 75

= 48 + 75

= 123 minutes

Lastly, Tyler practiced for <u>123 minutes</u>

8 0

2 years ago

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

2 years ago