<u>Given</u>:
The length of DE is 8 cm and the measure of ∠ADE is 60°.
We need to determine the surface area of the pyramid.
<u>Length of AD:</u>
The length of AD is given by
Length of AD = 8 cm
<u>Slant height:</u>
The slant height EF can be determined using the trigonometric ratio.
Thus, we have;
Thus, the slant height EF is 4√3
<u>Surface area of the square pyramid:</u>
The surface area of the square pyramid can be determined using the formula,
Substituting the values, we have;
The exact form of the area of the square pyramid is
Substituting √3 = 1.732 in the above expression, we have;
Rounding off to one decimal place, we get;
Thus, the area of the square pyramid is 174.8 cm²
Answer:
-a + b
Step-by-step explanation:
Answer:
2063.9 kg
Step-by-step explanation:
Given,
<u>1 kg = 2.2046 pounds</u>
This can also be written as:
<u>1 pound = 1/2.2046 kg</u>
We have to calculate the value of 4550 pounds in kg up to nearest 10th
Thus,
Solving the above equation, we get:
4550 pounds = 2063.8664 kg
Rounding the above result to nearest tenth as:
<u>4550 pounds = 2063.9 kg</u>
the is c.32$&$&#&#
Step-by-step explanation:
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Answer:
The most logical answer is D
Step-by-step explanation: