Answer:
0.6 is the probability of success of a single trial of the experiment
Complete Problem Statement:
In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by
What is the probability of success of a single trial of this experiment?
Options:
Step-by-step explanation:
So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:
=
now,
so,
by comparing with , we get:
μ=np=27
=3.29
put np=27
we get:
=3.29
take square on both sides:
10.8241=27-27p
27p=27-10.8241
p=0.6
Which is the probability of success of a single trial of the experiment
Answer:
A is 10 dollar cheaper than B
Step-by-step explanation:
A : 40 dollars plus 45*2=90
90+40= 130 dollars
B:100 dollars 45*1=45
100+45= 145 dollars
<h3>
<u>Explanation</u></h3>
- Convert the equation into slope-intercept form.
where m = slope and b = y-intercept.
What we have to do is to make the y-term as the subject of equation.
From y = mx+b, the slope is 3.
<h3>
<u>Answer</u></h3>
Answer: He is not correct.
Steps:
Let x1 and x2 be the first and second number, respectively.
In words, if the second is 125%, or 5/4 of the first number (first equation),
then the first is 4/5 of the second, which is 0.8 or 80%.
Answer:
He has to buy 4 packages of hamburgers in packages of 30 and 5 packages of hamburgers in packages of 24
Step-by-step explanation:
First we have to calculate the least common multiple (LCM) of 24 and 30
We will calculate the LCM of 24 and 30 by prime factorization method
24 = 2*2*2*3 =
30 = 2*3*5 =
LCM =
LCM = 120
So number of hamburger buns = 120
Therefore, he must buy 120/24 = 5 packages of hamburgers in packages of 24 and he must also buy 120/30 = 4 packages of hamburgers in packages of 30