Answer: liain is using lucid mode
Explanation:btw im from canida so sorry if its wrong
Answer:
a = 2.72 ms⁻²
32.83 s
Explanation:
By using the kinematic equations you get,
v² = u² +2as and v = u + at where all terms in usual meaning
Using 1st equation,
89.3² = 0² + 2a×1465 ⇒ a = 2.72 ms⁻²
By 2nd equation,
89.3 = 0 + 2.72×t ⇒ t = 32.83 s
The initial value of P*V = 0.100*150 atm-m³
<span> Each balloon has a volume of (4/3)*π*r³ and N balloons have a volume of N*(4/3)*π*r³
</span><span> When all the balloons are inflated, the pressure in the tank is the same as the pressure in the balloons, so the final value of P*V is
</span><span> 1.20*[N*(4/3)*π*r³ + 0.100]
</span><span> 0.100*150 = 1.20*[N*(4/3)*π*r³ + 0.100] solve for N:
</span><span> 15/1.2 = N*(4/3)*π*r³ + 0.100
</span><span> 12.5 - 0.100 = N*(4/3)*π*0.150³
</span><span> 12.4 = N*0.01414
</span><span> N = 877</span>
1 would use less energy. Please vote my answer brainliest! Thanks.
Answer:
A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes
Explanation:
Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
where,
Vf = Final Velocity of Car = 0 mi/h
Vi = Initial Velocity of Car = 50 mi/h
a = deceleration of car
s = distance covered
Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.
So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:
s = vt
FOR SOBER DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 0.33 s
s = s₁
Therefore,
s₁ = (73.33 ft/s)(0.33 s)
s₁ = 24.2 ft
FOR DRUNK DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 1 s
s = s₂
Therefore,
s₂ = (73.33 ft/s)(1 s)
s₂ = 73.33 ft
Now, the distance traveled by drunk driver's car further than sober driver's car is given by:
ΔS = s₂ - s₁
ΔS = 73.33 ft - 24.2 ft
<u>ΔS = 49.13 ft</u>
