Answer:
21 consonant tiles
Step-by-step explanation:
Henry has a bag containing 39 letter tiles, some consonants, and some vowels.
He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?
Step 1
We add up the number of tiles that he pulls out of the bag
= 7 consonant tiles + 6 vowel tiles
= 13 tiles
Step 2
We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag
= 39 tiles ÷ 13 tiles
= 3
Step 3
The most likely number of consonant tiles in Henry's bag is calculated as:
3 × The number of consonant tiles that was pulled out of the bag.
Hence:
3 × 7 consonant tiles
= 21 consonant tiles.
Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.
Answer:
There was a 25% increase.
Step-by-step explanation:
Answer:
4x+13
Step-by-step explanation:
combine like terms -2x and 6x to get 4 then combine 9 and 4 to get 13
90° is the correct answer
Answer: 15 / 56
Step-by-step explanation:
Number of red checkers = 3
Number of black checkers = 5
Total number of checkers = 8
P(black, then red) = 5/8 × 3/7 = 15/56
We should note that the probability to pick a black checker first will be 5 out of 8. Then, there'll be 7 checkers left and the probability to pick a res checker will be 3/7. We then multiply the probabality of each together.
