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2 years ago

A windmill converts the mechanical energy of wind into ?

Physics

1 answer:

sammy [17]2 years ago

7 0

Electric power most likely. It can be a generator for a power plant if needed. Hope this helped. Sorry if it didn't.

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If there are 60 min in 1hr, and in 1min there are 60 sec; Solve the following problem using dimensional analysis.: 3,800 hrs. to

GREYUIT [131]

13680000 should be the number of seconds

6 0

2 years ago

All household circuits are wired in parallel. A 1140-W toaster, a 270-W blender, and a 80-W lamp are plugged into the same outle

VARVARA [1.3K]

Answer:

total current = 12.417 A

so it will not fuse as current is less than 15 A

Explanation:

given data

toaster = 1140-W

blender = 270-W

lamp = 80-W

voltage = 120 V

solution

we know that current is express as

current = power ÷ voltage ......................1

here voltage is same in all three device

current by toaster is

I = $\frac{1140}{120}$

I = 9.5 A

and

current by blender

I = $\frac{270}{120}$

I = 2.25 A

and

current by lamp is

I = $\frac{80}{120}$

I = 0.667 A

so here device in parallel so

total current is = 9.5 A + 2.25 A + 0.667 A

total current = 12.417 A

so it will not fuse as current is less than 15 A

8 0

2 years ago

Need Help ASAP!!<br> (Picture)

olchik [2.2K]

Answer:225000000000

Explanation:

5 0

2 years ago

A distorted 1kHz sine wave is represented by the equation: LaTeX: v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)v ( t ) = 5 s i

vovikov84 [41]

Answer:

As given in the problem statement

frequency=1 KHz=1*10^3 Hz

V(t) is represented as

v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)

v ( t ) = 5 s i n ( 2 π 1000 t ) + 0.05 s i n ( 2 π 3000 t )

Total harmonic distortion will be 234 Pi

3 0

2 years ago

An intravenous (IV) system is supplying saline solution to a patient at the rate of 0.06 cm3/s through a needle of radius 0.2 mm

horsena [70]

Answer:

Pressure applied to the needle is 7528 Pa

Explanation:

As we know by poiseuille's law of flow of liquid through a cylindrical pipe

the rate of flow through the pipe is given as

$Q = \frac{\Delta P \pi r^4}{8\eta L}$

now we know that

$Q = 0.06 \times 10^{-6} m^3/s$

radius = 0.2 mm

Length = 6.32 cm

$\eta = 1\times 10^{-3} Pa s$

now we have

$6 \times 10^{-8} = \frac{\Delta P \pi (0.2 \times 10^{-3})^4}{8(1 \times 10^{-3})6.32 \times 10^{-2}}$

$3.03 \times 10^{-11} = \Delta P 5.02 \times 10^{-15}$

$\Delta P = 6028 Pa$

now we have

$P - 1500 = 6028 Pa$

$P = 7528 Pa$

8 0

2 years ago