Convert them to comparable thingummys
convert to fraction
percent means parts out of 100
30%=30/100=3/10
3/10 vvs 1/3
make bottom number 30
3/10 times 3/3=9/30
1/3 times 10/10=10/30
10/30>9/30
1/3 is bigger
Answer: It is not possible that two triangles that are similar and not congruent in spherical geometry.
Step-by-step explanation:
For instance, taking a circle on the sphere whose diameter is equal to the diameter of the sphere and inside is an equilateral triangle, because the sphere is perfect, if we draw a circle (longitudinal or latitudinal lines) to form a circle encompassing an equally shaped triangle at different points of the sphere will definately yield equal size.
in other words, triangles formed in a sphere must be congruent and also similar meaning having the same shape and must definately have the same size.
Therefore, it is not possible for two triangles in a sphere that are similar but not congruent.
Two triangles in sphere that are similar must be congruent.
Step-by-step explanation:
To solve a compound inequality, first separate it into two inequalities. Determine whether the answer should be a union of sets ("or") or an intersection of sets ("and"). Then, solve both inequalities and graph.
Hopes this helps.
Answer:
D) q + d = 330
0.25q + 0.1d = 6
Step-by-step explanation:
Let q= numbers of quarters
d = number of dimes
q + d = 33 ...........(1)
q = 33 - d
xq + yd = 6 ..........(2)
We will consider the options to know the correct answer
From option A
q +d = 6
25q + 10d = 33
This is wrong
Option B
q + d = 60
0.25q + 0.1d = 33
This is also wrong
Option C
q+d = 33
25q + 10d = 6
Put q = 33 -d in equation 2
25(33 - d) + 10q = 6
825 - 25d + 10d = 6
825 - 15d = 6
-15d = 6-825
-15d = -819
d = -819/-15
d= 54.6
This is also wrong because d exceeds the combination.
Option D
q+d = 33
0.25q + 0.1d = 6
Put q = 33 -d in equation 2
0.25(33 - d) + 0.1d = 6
8.25 - 0.25d + 0.1d = 6
8.25 - 0.15d = 6
-0.15d = 6 - 8.25
-0.15d = -2.25
d = -2.25/ -0.15
d = 15
q = 33 - 15
q = 18
This is correct
<span>Please be more clear with what you want for your answer. </span>
