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2 years ago

7

Symbols The difference in speeds of El Toro and T Express is 5 miles per hour. If El Toro has the greater speed, write and solve

a subtraction equation to determine its speed.

2 answers:

uysha [10]2 years ago

7 0

Answer: Let's call Vt and Ve to bout velocities.

you know that Vt>Ve and that Vt - Ve=5

so Vt = 5 + Ve.

and you can check that Vt is 5 miles per hour greater than Ve.

So if you know the vale of Vt or the value of Ve, with that equation you can obtain the other velocity.

Maslowich2 years ago

5 0

Let the speed of El Toro be x mph and that of T Express be y mph.

Given : Speed of El Toro > Speed of T Express

i.e, x > y

Also, the difference in the speeds of El Toro and T Express is 5 mph.

So, the required equation is

x - y = 5

To determine the speed of a train, the speed of other is required.

The speed of El Toro = Speed of T Express + 5

The speed of T Express = Speed of El Toro - 5

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Simplify each expression then factor the expression 14-28t-5(7+10t)

ludmilkaskok [199]

Answer:

Simplified: -21-98t

Factored: -7(14t+3)

Step-by-step explanation:

The given expresion is:

14-28t-5(7+10t)

We expand the parenthesis to get:

$14 - 28t -35 - 70t$

We group like terms to get:

$14 -35 - 28t- 70t$

We combine similar terms to get:

$- 21- 98t$

We now factor to obtain:

$- 21- 98t = - 7(14t + 3)$

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2 years ago

over 5 days 8,208 people visited the amusement park about how people visited the park per day using rates

Nadusha1986 [10]

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2 years ago

WILL GIVE BRAINLIEST!!

VMariaS [17]

Answer:

$A(-1,4)\to A''(-1,-1)$

$B(0,2)\to B''(1,0)$

$C(1,2)\to C''(1,1)$

$D(-2,4)\to D''(-1,2)$

Step-by-step explanation:

The given trapezoid has vertices at A(−1,4), B(0,2), C(1,2) and D(2,4).

The transformation rule for 90° counterclockwise rotation is

$(x,y)\to(-y,x)$

This implies that:

$A(-1,4)\to A'(-4,-1)$

$B(0,2)\to B'(-2,0)$

$C(1,2)\to C'(-2,1)$

$D(2,4)\to D'(-4,2)$

This is followed by a translation 3 units to the right.

This also has the rule: $(x,y)\to (x+3,y)$

$A'(-4,-1)\to A''(-1,-1)$

$B'(-2,0)\to B''(1,0)$

$C'(-2,1)\to C''(1,1)$

$D'(-4,2)\to D''(-1,2)$

Therefore:

$A(-1,4)\to A''(-1,-1)$

$B(0,2)\to B''(1,0)$

$C(1,2)\to C''(1,1)$

$D(-2,4)\to D''(-1,2)$

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2 years ago

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const2013 [10]

The answer you are looking for is -17/44

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2 years ago

Read 2 more answers

Can you break down how to solve the problem ?

Montano1993 [528]

Answer:

A. y = $\frac{-5x}{2}$ - 1

Step-by-step explanation:

Given parameters:

Equation of the line:

5x + 2y = 12

Coordinates = -2, 4

Unknown:

The equation of the line parallel to this line = ?

To solve this problem, first, we need to find the slope of the given line.

Every linear equation have the formula: y = mx + c

m is the slope of the line, c is the y- intercept

5x + 2y = 12

Express this equation as y = mx + c

2y = -5x + 12

y = $\frac{-5}{2}x$ + 6

The slope of this line is $\frac{-5}{2}$

Now, any line that is parallel to another will not cut or cross it at any point. This simply implies they have the same slope.

Slope of the line parallel is $\frac{-5}{2}$

Our new line will also take the form y=mx + c,

Coordinates = -2, 4, x = -2 and y = 4

m is $\frac{-5}{2}$

Now let us solve for C, the y-intercept;

4 = - 2 x $\frac{-5}{2}$ + C

4 = 5 + C

C = -1

The equation of the line is therefore;

y = $\frac{-5x}{2}$ - 1

6 0

2 years ago