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2 years ago

How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8%

Mathematics

1 answer:

Likurg_2 [28]2 years ago

4 0

Answer:

x+y=40liters

10%x+5%y=8%×40

(2x+y)/20=8%×40

(2x+y)=64

x=24

y=16

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