Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
Answer
Step-by-step explanation:
Answer:
2/3 cup
Step-by-step explanation:
first you need to convert the fractions so that they have the same denominator (1/3 turns into 2/6)
then you just add up the numerators (2+2=4..... 4/6)
you can stop there or you can simplify it (4/6 turns into 2/3)
Answer: how do you solve for this
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
f(x) - g(x) = -9x^2 - 7x + 12 - (3x^2 - 4x - 15) Remove the brackets
f(x) - g(x) = -9x^2 - 7x + 12 - 3x^2 + 4x + 15
f(x) - g(x) = -9x^2 - 3x^2 - 7x + 4x + 12 + 15
f(x) - g(x) = -12x^2- 3x + 27
Answer D