For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
36/39 or 12/13 is th answer to that
Answer:
c
Step-by-step explanation:
because I had a test on these
40+90=130
180-130=50
50+130=180
x=130
50+x=180
Answer:
a. 0.12109
b. 0.0001668
c .0.9726
d. 0.01038
e. 0.01211
f. 0.000001731
Step-by-step explanation:
Sample size = 580
Defective units = 8
Number of picks = 2
a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:
b) The probability that both are defective is given by:
c) The probability that both are acceptable is given by:
d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:
e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:
f) The probability that all three are defective is given by: