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2 years ago

I need help on this question

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

3 0

Diagonal, I hope I helped (:

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Find the value of x in the triangle shown below. X=____ Please help!!

Misha Larkins [42]

Answer:

Step-by-step explanation:

the sum of all angles in a triangle should be 180°

180-56= 124

124÷2= 62

x= 62

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2 years ago

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Keith has 7 yards of string. He needs ⅓ yard of string for each of his puppets. How many puppets can Keith make with his string?

Pani-rosa [81]

Answer:

the no of puppets that could be made with his string is 21

Step-by-step explanation:

Given that

There is 7 yards

And, it needs one -third of string for each of his puppets

= 7 × 3

= 21 puppets

We simply multiply the 7 yards with the 3 so that the no of puppets could come

hence, the no of puppets that could be made with his string is 21

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2 years ago

The length of a rectangular garden is 9 feet longer than its width. If the garden's perimeter is 194 feet, what is the area of t

Natasha_Volkova [10]

194 feet

Answer: 195 feet

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2 years ago

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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

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2 years ago

What is equivalent to y+4(x-5)+4y?

Inessa [10]

4(x-5)+5y is your answer

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2 years ago