A football is thrown vertically with an initial velocity of 33m/s. Calculate the velocity of the ball when it’s height increased
1 answer:
The final velocity becomes 31.48 m/s
<u>Explanation:</u>
Given:
Initial velocity, u = 33 m/s
Height, h = 5m
Final velocity, v = ?
According to Newton's law:
v² - u² = 2gh
where,
g is the acceleration due to gravity and
g = 9.8 m/s²
On substituting the values we get:
Therefore, the final velocity becomes 31.48 m/s
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Answer:
The submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³
Explanation:
Given;
wet density of soil sample = 2.5 Mg/m³ = 25 kN/m³
Specific gravity of solid particle = 2.7
The dry unit weight of soil;
for undisturbed state, the volume of the soil is;
Submerged effective density is given as;
density of water (ρw) = 2.7 x 25 kN/m³ = 67.5 kN/m³, substitute this in the above equation;
Therefore, the submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³
The gravitational force between the objects is
Explanation:
The magnitude of the gravitational force between two objects is given by the equation:
where
is the gravitational constant
are the masses of the two objects
r is the separation between the objects
For the two objects in this problem:
And their distance is
r = 2.6 m
So, the gravitational force between them is
Learn more about gravitational force:
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