The moles can be defined as the mass of the substance with respect to molar mass. The moles of potassium nitrate is 1 mol.
<h3>How to calculate moles of a substance?</h3>
The moles of a compound can be calculated from:
The molarity can be defined as the moles of solute in a liter of solution.
The molarity can be expressed as:
The molarity of potassium nitrate solution is 2 M, and the volume is 500 mL.
The moles of potassium nitrate is given as:
The moles of potassium nitrate in 2 M, 500 mL solution are 1 mol.
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brainly.com/question/15209553
Answer:
The products react to reform the original reactants
E.g. Haber process of ammonia production
Answer:
The halogens, nitrogen and sulphur are covalently bonded to the organic compounds. In order to detect them, the elements need to be converted into their ionic forms. This is done by fusing the organic compound with sodium metal. ... The extract is called sodium fusion extract or Lassaigne's extract.
<em>Explanation:</em>
<em>safety precautions to be taken when performing diluting concentrated sulphuric acid with water</em>
- Using gloves while diluting to avoid injury from hot sulfuric acid to hands.
- Wearing safety glasses to protect eyes
- Must wear lab coat before performing any chemistry practical
- Safety boots to protect your legs.
Answer:
Explanation:
A mole is any quantity of a substance that contains 6.02 × 10²³ particles. At standard temperature and pressure, or STP, 1 mole of as is equal to 22.4 liters. This is true for any gas, regardless of the specific kind.
Although it is not specified, we can assume this gas is at STP. Let's set up a ratio using this information: 22.4 L/mol
Multiply by the given number of liters: 12
Flip the ratio so the liters of chlorine cancel.
The original measurement of liters has 2 significant figures, so our answer must have the same.
For the number we found, that is the hundredth place.
The 5 in the thousandth place tells us to round the 3 up to a 4.
12 liters of chlorine gas at STP is approximately <u>0.54 moles of chlorine gas.</u>
