Solve by square roots 4x^2+11= 59
2 answers:
Subtract 11 from each side
4x^2+11-11= 59-11
4x^2 = 48
Divide by 4
4/4x^2 = 48/4
x^2 = 12
Take the square root of each side
sqrt(x^2) = sqrt(12)
x = ±sqrt(4 x 3)
Answer:
x= ±2 sqrt(3)
Step-by-step explanation:
4x^2+11= 59
Subtract 11 from each side
4x^2+11-11= 59-11
4x^2 = 48
Divide by 4
4/4x^2 = 48/4
x^2 = 12
Take the square root of each side
sqrt(x^2) = sqrt(12)
x = ±sqrt(4*3)
x= ±2 sqrt(3)
You might be interested in
Those expressions are already in scientific notation.
To solve this, you would do:
x + 75% * x = 35
7/4 * x = 35
x = 20
X^2-81=x^2-9^2=(x+9)(x-9)
this is the answer
Answer:
smaller number = 15
Step-by-step explanation:
Let the two numbers be 5x and 3x respectively.
According to the question —
5x — 3x = 10
2x = 10
x = 5
Thus the smaller number is 3 × 5 = 15
If a binomial x-a is a factor of a polynomial p(x), then p(a)=0.
x+2 is a factor of p(x)=x³-6x²+kx+10, so p(-2)=0.
