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2 years ago

Can someone please help me?:\

Mathematics

1 answer:

katrin [286]2 years ago

7 0

The circumference of the top of the cake is $9.5\pi\approx29.845$ in.

It sounds like the baker is trying to line the circumference with cherriesto fit as many as possible along the border, like in the picture I've attached below.

This comes down to dividing the cake's circumference by the diameter of each cherry:

$\dfrac{9.5\pi}{0.75}\approx39.79$

or about 39 cherries, making the answer D.

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Complete the two-column proof by providing a reason for each of the five statements.

Mnenie [13.5K]

Answer:

Step-by-step explanation:

Given:

RUTS is a rectangle.

To prove:

∠USR ≅ ∠SUT

Statements Reasons

1. RUTS is a rectangle 1. Given

2. RU = ST, UT = RS 2. By the definition of a rectangle

3. ∠STU = ∠SRU = 90° 3. Definition of a rectangle

4. ΔURS ≅ ΔSTU 4. By the LL theorem of congruence

5. ∠USR ≅ ∠SUT 5. CPCTC

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2 years ago

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8_murik_8 [283]

2(x +4)-6(q/9)

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2 years ago

Plz help with these first one gets brainliest

vlabodo [156]

Answer:

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Step-by-step explanation:

Its the absolotle value between them.

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2 years ago

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Simplify: - 4x 5x - 1 + 3-6x 3-6x

Vitek1552 [10]

Answer:

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2 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

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11 months ago